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[hv=d=n&v=n&n=skt74hkj95d76cjt8&s=saq3haq8dj8432ca9]133|200|Scoring: MP

1NT 2C

2D 2NT

3NT

 

Ten of diamonds led to the King. King of clubs returned.[/hv]

 

SOUTH is declarer.

 

Curious what the best way forward is. I suspect you'll convict me, but I'll let you know either way.

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You have eight tricks developed, and the fact that they lead diamonds may allow you to be able to have the timing needed to get that ninth tricks. My gut reaction is to return a club to the J and let them untangle things. The question is, where's the diamond honors - the lead of the T, can be from H-T-x, T-9-x, T-8-x, top of nothing, or more.

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This is MP. It looks like the odds of the lead being from AQ109 precisely to be less than the spade Q coming down. So play as suggested by Orlam. If all goes well you could make an overtrick.
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Look at it from your RHO's point of view.

You are 100% certain what his diamond holding is.

I am?

 

Ok, here goes.

 

LHO has the 9.

RHO had the King

RHO did not have the Q, or he would have played it.

LHO did not have the A, or he would not have underled it?

 

So LHO started wtih AK8.

 

How did I do?

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Look at it from your RHO's point of view.

You are 100% certain what his diamond holding is.

I am?

 

Ok, here goes.

 

LHO has the 9.

RHO had the King

RHO did not have the Q, or he would have played it.

LHO did not have the A, or he would not have underled it?

 

So LHO started wtih AK8.

 

How did I do?

You can see the 8.

 

LHO must have the Q, T, and 9, right? But he wouldn't lead diamonds if that's all he had. So it must be one of:

 

QT95 AK

AQT9 K5

AQT95 K

 

If it was the middle one, surely RHO would return a diamond.

 

So RHO must have either AK or K stiff.

 

Edit: I keep thinking about the lead back of the king of clubs. Is he trying to establish an entry to partner? It is possible that his partner has QT9xxx so an entry would do the trick, but in that case if he has AK he should lead the second diamond before establishing an entry. That would mean the K only makes sense as an entry maker if he has the stiff king of diamonds.

 

The other possibility is that he's given up on the set and working on making sure they get 3 tricks. Give him, say...

 

Jxx

xxx

AK

KQxxx

 

 

Now you could have the other red queen (his partner only has 2 points):

 

AQ3

AT8

QJ432

A9

 

and have 4 spades, 4 hearts, 2 diamonds, and a club if he cashed the second diamond. Playing the king of clubs before cashing the second diamond holds it to 10 tricks.

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Warren, why didn't RHO play back another diamond?

With K, and KQ and some club length (unless clubs are 4/4, LHO is a great bet to have at least 5 from the lead), all you need to do is find partner with the Ax(x) of clubs and the contract is down.

 

If the K is single, I'm ok with that.

 

IF RHO started with the AK doubleton, he's cash the ace. If he started with the K8 doubleton, then I'm not sure whether club or diamond is better at trick 2. But do you really lead the T from AQT9??

 

If RHO started with AK8 (only three card holding I can see), hmm.. A then 8 trusts partner, I guess. (although establishing clubs might be right too?)

 

If RHO stared with AKQ8 (I considered T9 doubleton on my left at the table, but looking at what that leaves RHO that seems strange)....

 

If RHO started with AKQ98, then a diamond comes back.

 

At the table, I thought a fair bit about what LHO could hold. Picturing RHO's possible holdings leads me to some different conclusions.

 

...

 

I had a hard enough time puzzling out the T lead. Looking at possible RHO holdings isn't making opponents play a whole lot clearer.

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[hv=d=n&v=n&n=skt74hkj95d76cjt8&w=sj96ht63daqt9c543&e=s852h742dk5ckq762&s=saq3haq8dj8432ca9]399|300|Scoring: IMP[/hv]

 

West North East South

 

 -     Pass  Pass  1NT

 Pass  2    Pass  2

 Pass  2NT   Pass  3NT

 Pass  Pass  Pass  

 

 

 

 

I put up the ace, and returned a club. Diamonds were AQT9 on my left, and I was down.

 

Matchpoint score: 0%

 

Most people did NOT get a diamond lead, which I think made playing for 3/3 spades pretty easy. One other table did get a diamond lead (9 I think), and still played for the spade split.

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Has anyone ever worked out the odds of J dropping in 3 rounds in this situation? I would think it would be quite high.

 

The standard lead from AQT9 is the Ten, but many would be afraid of giving away an overtrick at matchpoints, and choose a safer lead.

 

Just think yourself very unlucky and move on to the next hand, East's play was illogical and fooled everyone. You would not duck Ace if you were wide open in Clubs, and even so, East should switch to a LOW club if he expected West to have Ax :(

 

Tony

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Oh dear, now I've seen RHO's hand, all I can say is your opponents have fooled me too...

 

On this start to the defence I would be 100% certain that the king of diamonds is singleton on my right.

 

The 10 of diamonds is the normal lead from honour holdings starting AQ109, A109, Q109 or 1098/1097. Looking at two low diamonds in dummy, how does your RHO know that your hand isn't something like

 

AQx

AQx

Jxxx

Axx

 

 

Or

 

Qxx

AQx

AJx

A9xx

?

(at trick 1 you have to guess whether to take or duck the diamond, depending on who has the ace of spades)

 

Most of the sensible world will have played a diamond back from the East hand looking at Kx, in case they were cashing five diamond tricks, so you know that's not his holding.

 

That being said, there are two reasons why you can make the contract anyway.

 

i) The king of clubs switch is almost certainly wrong whatever RHO's diamond holding, looking at J108 in dummy. If he's trying to cash the club suit, he should switch to a low one from KQxxx. That tells you he may not be the best player in the world.

 

ii) If RHO does have singleton king of diamonds, it doesn't hurt to cash three rounds of spades first, before playing a club, because they will never be able to take more than four tricks when they get in.

 

(matchpoints is a different matter. I'd play a club back at once, because I may be able to generate a 10th trick)

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Has anyone ever worked out the odds of J dropping in 3 rounds in this situation? I would think it would be quite high.

Slightly better than 50% as the majority of the other spades are more likely to be in the 13 slots without the jack than in the 12 slots with the jack.

 

Of course you have the added chance that RHO shows out on the second round so you can finesse.

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I think as mentioned previously, playing Q then A spades doesn't do any harm. You might even get a count signal from your opponents which could help in sorting out the spade situation before you take any further action.
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