shevek Posted January 31, 2009 Report Share Posted January 31, 2009 [hv=d=s&v=e&s=skj96542h73da5cqt]133|100|Scoring: IMPYou deal and ...[/hv] Quote Link to comment Share on other sites More sharing options...
JLOL Posted January 31, 2009 Report Share Posted January 31, 2009 1S seems obvious at this vul, wouldn't mind 2 if red/white. Quote Link to comment Share on other sites More sharing options...
mtvesuvius Posted January 31, 2009 Report Share Posted January 31, 2009 1♠ for me. Quote Link to comment Share on other sites More sharing options...
JLOL Posted January 31, 2009 Report Share Posted January 31, 2009 Also I wish the D5 or S5 was an 8 then you would have 1 of every card. Quote Link to comment Share on other sites More sharing options...
mikestar Posted January 31, 2009 Report Share Posted January 31, 2009 I don't care to preempt with this one--too much chance that some random club holding in partner's hand can promote my ♣Q to a second defensive trick. Trading the ♣T for a small spade could tip my decision the other way--it's that close IMO, in which case I'd try 3♠. No way will I open a seven carder with a weak two at these colors. Quote Link to comment Share on other sites More sharing options...
Fluffy Posted January 31, 2009 Report Share Posted January 31, 2009 I would never open this 2♠, I like 1♠ best, then 3 and then 4. Quote Link to comment Share on other sites More sharing options...
maggieb Posted January 31, 2009 Report Share Posted January 31, 2009 1♠ by a mile. Quote Link to comment Share on other sites More sharing options...
skjaeran Posted January 31, 2009 Report Share Posted January 31, 2009 I play 2♠ as 8-11 with a 6-bagger. I'd not allow an extra spade at any colours when I'm in the upper range. So I open 1♠. Quote Link to comment Share on other sites More sharing options...
gwnn Posted January 31, 2009 Report Share Posted January 31, 2009 wow apparently there's only a .01% chance of that happening (one of each card) Quote Link to comment Share on other sites More sharing options...
jdonn Posted January 31, 2009 Report Share Posted January 31, 2009 wow apparently there's only a .01% chance of that happening (one of each card) Wow really that much? (52/52)*(48/51)*(44/50)*(40/49)*(36/48)*(32/47)*(28/46)*(24/45)*(20/44)*(16/43)*(12/42)*(8/41)*(4/40) = .00010568 I guess so. Surprised it's not smaller! Quote Link to comment Share on other sites More sharing options...
JLOL Posted January 31, 2009 Report Share Posted January 31, 2009 I have only noticed it twice but have probably had it much more if it is .01% Quote Link to comment Share on other sites More sharing options...
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