eros2 Posted December 20, 2008 Report Share Posted December 20, 2008 KQTxxx opposite x Please could someone kindly inform me of the odds of playing this fit for at most 2 losers by leading: 1) towards the K 2) towards the T And... 3) How much of a difference does the 9 spot make? i.e. the suit is now KQT9xx Thank you =] Quote Link to comment Share on other sites More sharing options...
foo Posted December 20, 2008 Report Share Posted December 20, 2008 The proper percentage play is x -> KQTxxx planning to insert the T unless 2nd hand plays high (obviously, you cover the J and duck the A) You've got a bit less than a 60% chance of bringing the suit home for no more than 2 losers. Do not play a high honor 3rd hand unless 2nd hand has inserted the J. Changing the long suit to KQT9xx changes both the odds and the proper play. The proper play here is dependent on whether you want to play for 5 tricks or 4. For a ~26% shot at 5 tricks, you play as above. For the maximum chance at 4 tricks, you plan to take the safety play of hooking the K rather than the T on T1. This makes the odds of taking 4 tricks just a bit less than 88%. Quote Link to comment Share on other sites More sharing options...
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