luke warm Posted April 11, 2004 Report Share Posted April 11, 2004 at a walddk tourney recently, here was the hand/bidding: [hv=d=s&v=a&n=s862haq7dk85ca732&w=st7h862d97642cjt8&e=sj953hjt94djtcq96&s=sakq4hk53daq3ck54]399|300|Scoring: IMP[/hv] West North East South - - - 2NT! Pass 4♣ Pass 4♠ Pass 6NT Pass Pass Pass i held the south hand.. 4♣ was gerber... a ♦ was led, won in hand, and a ♣ ducked immediately... 12 tricks made then, on the club break i looked at this hand later, most everyone made 6nt (one made 7), but very few ducked the club early... so my question is, what is the right way to play it? does the form of scoring matter? Quote Link to comment Share on other sites More sharing options...
dogsbreath Posted April 11, 2004 Report Share Posted April 11, 2004 duck a C looks automatic ..make on either black suit 3-3 and when one hand guards both blacks. rGDS Dog Quote Link to comment Share on other sites More sharing options...
inquiry Posted April 11, 2004 Report Share Posted April 11, 2004 Wrongway and Benway.... Ben ducks a ♣ at trick two... just like you. Ben Quote Link to comment Share on other sites More sharing options...
Free Posted April 11, 2004 Report Share Posted April 11, 2004 How will you ever get to 12 tricks? ♠ 3-3 or ♣ 3-3 or some stupid discard somewhere. So duck a ♣ and combine your chances... Quote Link to comment Share on other sites More sharing options...
luke warm Posted April 11, 2004 Author Report Share Posted April 11, 2004 the hands i looked at, where the club wasn't ducked, east almost always threw away a spade... when dummy came down, i had 11 tricks... so i figured my hopes were as you said free, combine the chances of 3/3 blacks OR hope same person had 4/4 blacks... i can't see how the form of scoring would matter here... it seems that ducking a club is the only real way to make the hand, unless there's misdefense Quote Link to comment Share on other sites More sharing options...
inquiry Posted April 11, 2004 Report Share Posted April 11, 2004 How will you ever get to 12 tricks? ♠ 3-3 or ♣ 3-3 or some stupid discard somewhere. So duck a ♣ and combine your chances... Duck a ♣ gives you serious chance if neither black suit is split 3-3. This is squeeze 101. You have 11 tricks (3♠+3♥+3♦+2♣). You have two losers. In squeeze, the concept is to correct the count as soon as possible. Thus, duck a ♣. Now, if someone has both four ♠ and four ♣, they are exposed to an automatic simple squeeze. Win the return and cash all red suit winners. To see how this might work, exchange the ♣J and ♥J between opponent's hand. Now, EAST with only five red cards, has to discard a black card on the last red winner. IF ♣, ♣'s run, if ♠, they run. Simple. You could cash all the black winners in one suit if you like (after ducking the ♣, as long as you win the last red card winner in the hand with the fourth card in that black suit, of course. Ben Quote Link to comment Share on other sites More sharing options...
Free Posted April 11, 2004 Report Share Posted April 11, 2004 Jup, as Jimmy said: "one person has 4-4 blacks" (I forgot this one ;) ), then you get an automatic squeeze... Quote Link to comment Share on other sites More sharing options...
Trpltrbl Posted April 14, 2004 Report Share Posted April 14, 2004 Duck the ♣, rectify the count. And onwards we go. Mike B) Quote Link to comment Share on other sites More sharing options...
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