matmat Posted August 28, 2008 Report Share Posted August 28, 2008 how many losers (according to the LTC) is the suit:A9xxxxxx? Quote Link to comment Share on other sites More sharing options...
effervesce Posted August 28, 2008 Report Share Posted August 28, 2008 Two losers. One loser per A/K/Q missing in a suit. If partner has xx support (a reasonable chance), it's likely to have just one loser so treating it as 1 loser ok. Quote Link to comment Share on other sites More sharing options...
P_Marlowe Posted August 28, 2008 Report Share Posted August 28, 2008 2. But the LTC works not very well for 7-2 fits, and similar for 8-? fits.As it is, if you indicate to partner, that you have a long suit, he should switch to counting cover cards instead of counting loosers. With kind regardsMarlowe Quote Link to comment Share on other sites More sharing options...
pclayton Posted August 28, 2008 Report Share Posted August 28, 2008 If you are into this kind of voodoo, I'd evaluate it is as 1.5 losers (average 1.7 around the table). If pard raises, then its 1/2. Quote Link to comment Share on other sites More sharing options...
helene_t Posted August 28, 2008 Report Share Posted August 28, 2008 An ace is - 1 1/2 loser so it's 3 - 1 1/2 = 1 1/2 loser. Of course common sense says that with such such a long suit you must sometimes subtract from 2 rather than 3. If I were to formalize LTC for 8-cards I would take the probability that no opp has a 3-card into account. I suppose it would be something like 1 LTC for this hand. Quote Link to comment Share on other sites More sharing options...
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