haben12 Posted June 17, 2008 Report Share Posted June 17, 2008 This part had to be written new, because the used table has been destroyed by the editor. :P Realization of these 2 ideas:..........................................................................................Abbr.: Enq.= Enquirer ¦¦ Res. = Responder ¦¦ AsKs = sum of Aces and Kings.......................................................................................... 1. ..... (look at the acticle) 2. If the Enq. will know the AsKs of the P., (s)he has 2 possibilities to do that: 4 ♣ or 4 ♦. This depends on his own AsKs:When Enq. has 3 or 4 AsKs, the question is 4 ♣, when (s)he has 5 (or even more), the question is 4 ♦.The advantage of this question choice is: The Res. knows rather exactly too, how many controls the Enq. has (the minimum exactly). The Res.´s answers after 4 ♣: 4 ♦: 0 - 2 AsKs (no slam possible) minimum together 34 ♥: 3 AsKs and neighter Single nor a void min. together 64 ♠: 3 od. 4 AsKs and either a Single or a void min. together 64 NT: 4 AsKs and neither a Single nor a void min. together 75 ♣: 5 AsKs 8 The Res.´s answers after 4 ♦: 4 ♥: 0 or 1 AsKs and neither a Single nor a void min. together 54 ♠: 1 or 2 AsKs and either a Single or a void min. together 64 NT: 2 AsKs and neither a Single nor a void min. together 75 ♣: 3 AsKs 8 The rebids of the Enq.: .......(Look at the article) Quote Link to comment Share on other sites More sharing options...
TylerE Posted June 17, 2008 Report Share Posted June 17, 2008 Sorry, but I think this method is very poor. Give up useful natural cuebids/splinters to basically play 'double gerber'? Bids that both ask and tell are wasteful. Also, I see that you are not showing the trump queen, either. In addition, in this scheme, as far as I can tell, there is no way to tell the difference between being off 2 A's and 2 K's! If you really want this kind of thing, the responses can be structured much better. Here's a scheme I just brewed up. 4♣ - General keycard ask-4♦ - Bad hand for slam. 2 or fewer keycards-4♥ - 3-4♠ - 3 + TQ-4NT - 4-5♣ - 4 + Q After a 4♥+ response, cheapest non-signoff asks for # of side kings, in steps After 4♦, cheapest non-signoff bid reasks, then: 1st Step - 02nd Step - 13rd Step - 24th Step - 2 + TQ Then asker can relay again for side kings. (Note: I'm not seriously suggesting playing this, but I think it is less bad.) Quote Link to comment Share on other sites More sharing options...
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