nige1 Posted May 5, 2008 Report Share Posted May 5, 2008 [hv=d=w&v=n&n=s9ha53d854cakqj72&w=sa7643hqt72dj76c9&e=sjt52h986dk932c86&s=skq8hkj4daqtct543]399|300|Scoring: IMPInteresting Board 8 from the Spring 4s Round 4. South can make a small slam in no-trump or clubs but North makes neither against best defence according to Deep Finesse. Can you explain why without resorting to a computer program?[/hv] Quote Link to comment Share on other sites More sharing options...
Apollo81 Posted May 5, 2008 Report Share Posted May 5, 2008 I'm not going to think about notrump, but this is how it would go in 6♣: Clearly West cannot ever lead a major. If he leads a diamond, he can be endplayed with the ♠A, so he must lead a trump. North wins and knocks out the ♠A. West returns a diamond to the ♦K and ♦A. North plays three more trumps, East pitching a spade and a diamond, West pitching three spades. North leads the fifth trump. East cannot pitch a spade, so he pitches a red card. If a heart, North pitches a heart from dummy, crosses to the ♥K, cashes the ♠K pitching a diamond, and ruffs a spade. On this last play, West is squeezed in the red suits. If a diamond, North pitches a diamond from dummy, crosses to the ♦A (dropping East's last diamond), cashes the ♠K and ruffs a spade. West is squeezed in the red suits. If East was on lead, he would lead diamonds. This would remove one of the vital entries to dummy when West wins the ♠A and returns a diamond. Quote Link to comment Share on other sites More sharing options...
inquiry Posted May 5, 2008 Report Share Posted May 5, 2008 A low diamond lead from WEST destroys 6NT. Here is the winning line without that diamond lead (from WEST). NS have 6 clubs, 2 hearts, 1 Spade, and 2 diamonds. Let's say (for sake of argument) lets lead the spade jack and dummy plays the KING. If WEST wins, it corrects the count for a squeeze. After a tame club return EAST will have to give up either diamonds or hearts to protect spades. When he does, this becomes either a double squeeze (if he gives up hearts) or a simple squeeze (if he gives up diamonds). Possible endings are: [hv=n=shaxxdxc&w=shqtxdjc&e=sth9xxdc&s=sqhkjxdc]399|300|East throws away diamonds. Play ♠Q, west has to keep ♦, so comes to two hearts. AKJ of hearts win last three tricks. [/hv][hv=n=shaxxdxc&w=shqtxdjc&e=sth9xxdc&s=sqhkjxdc]399|300|East throws away diamonds. Play ♠Q, west has to keep ♦, so comes to two hearts. AKJ of hearts win last three tricks. [/hv] What this means is WEST can not correct the count by winning the first spade. However, his heart queen is "vulnerable" so if he ducks the first spade, he is exposed to a vulnerable stopper squeeze. After the first spade wins, (And a diamond to the queen wins)... run the clubs to reach something like this.... [hv=n=shaxxdxc&w=shqtxdjc&e=sth9xxdc&s=sqhkjxdc]399|300|East throws away diamonds. Play ♠Q, west has to keep ♦, so comes to two hearts. AKJ of hearts win last three tricks. [/hv] The diamond lead from WEST will destroy the late entry in diamonds needed for the squeeze to work. Dummy wins the queen, now on a spade, the spade ACE can win and the diamond JACK destroys the entry conditions. True EAST appears to be squeezed in diamonds and spades, BUT there is no entry in either suit, so the squeeze fails. Diamond lead from other side will not work, because after the spade ace is won, there is no way to knock out the diamond entry. Quote Link to comment Share on other sites More sharing options...
ArtK78 Posted May 5, 2008 Report Share Posted May 5, 2008 I'm not going to think about notrump, but this is how it would go in 6♣: Clearly West cannot ever lead a major. If he leads a diamond, he can be endplayed with the ♠A, so he must lead a trump. North wins and knocks out the ♠A. West returns a diamond to the ♦K and ♦A. Why would West return a diamond? Why not a spade? Seems to me that makes South's job much tougher, if not impossible. This assumes, of course, that declarer did not run the ♠9 if East does not split. Is there a reason for East to split? Is there a reason for declarer to run the ♠9? Quote Link to comment Share on other sites More sharing options...
nige1 Posted May 5, 2008 Author Report Share Posted May 5, 2008 Appolo8 and Inquiry have covered most possibilities. The solution seems to be a compund squeeze.A low diamond lead from WEST destroys 6NT. If West leads a ♦6 then East must play ♦K and South wins ♦A. Now when declarer crosses to ♣A and and leads ♠9 to ♠T and ♠Q, West has a problem. :(Why would West return a ♦? Why not a ♠? Seems to me that makes South's job much tougher, if not impossible. This assumes, of course, that declarer did not run the ♠9 if East does not split. Is there a reason for East to split? Is there a reason for declarer to run the ♠9?Sorry, Just to clarify: it is assumed that everybody plays double dummy. For example, assume that West leads ♣9 and exits with ♦6 when in with ♠A :ph34r: B) :P Quote Link to comment Share on other sites More sharing options...
david_c Posted May 5, 2008 Report Share Posted May 5, 2008 So the "main line" is club lead won in dummy, spade from dummy covered by East and South and won by West; then West leads a diamond to the king and ace. I think that's the key - West is endplayed into leading a diamond, forcing East to release his ♦K. Now isn't it just a standard double squeeze? You cash your other diamond and spade winners (pitching a diamond from dummy) and run the clubs (pitching a heart on the fifth club). East has the spade guard and West has the diamond guard, so neither can keep hearts as well. Quote Link to comment Share on other sites More sharing options...
nige1 Posted May 5, 2008 Author Report Share Posted May 5, 2008 Now isn't it just a standard double squeeze? You cash your other diamond and spade winners (pitching a diamond from dummy) and run the clubs (pitching a heart on the fifth club). East has the spade guard and West has the diamond guard, so neither can keep hearts as well. Yes, David appears to be correct. I thought it was a compound squeeze. But it seems it is not that complex. I think Inquiry's more interesting analysis comes into its own if you change the hands so that North has ♦432 and South has ♦AK5. Now, Deep Finesse says, with West on lead, only an initial ♦ defeats it :P Quote Link to comment Share on other sites More sharing options...
nige1 Posted May 6, 2008 Author Report Share Posted May 6, 2008 [hv=d=w&v=n&n=s2ha32da32cak9876&w=sa6543hj76dj76cjt&e=sqt98hqt98dqt98cq&s=skj7hk54dk54c5432]399|300|Scoring: IMPA simple layout showing what I mistakenly thought was a solution to the original problem. North or South can make 6♣ or 6N on any black suit lead by means of a compound squeeze.[/hv] Quote Link to comment Share on other sites More sharing options...
inquiry Posted May 6, 2008 Report Share Posted May 6, 2008 [hv=d=w&v=n&n=s2ha32da32cak9876&w=sa6543hj76dj76cjt&e=sqt98hqt98dqt98cq&s=skj7hk54dk54c5432]399|300|Scoring: IMPA simple layout showing what I mistakenly thought was a solution to the original problem. North or South can make 6♣ or 6N on any black suit lead by means of a compound squeeze.[/hv] Swap the spade 8 and spade six, and try to make it on a spade lead through the KJ. Quote Link to comment Share on other sites More sharing options...
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