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6 or 7 ?  

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  1. 1. 6 or 7 ?

    • 6NT
      3
    • 7NT
      26


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7 also, but I know what is going to happen;)

 

When J does not drop, you will have cold sweats whether to finesse the heart at trick 10, or play for the drop. Discards may reveal something, but good opposition will not tell you anything.

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7 also, but I know what is going to happen;)

 

When J does not drop, you will have cold sweats whether to finesse the heart at trick 10, or play for the drop. Discards may reveal something, but good opposition will not tell you anything.

But we are asked what contract we prefer, if we knew all cards. You don't have to sweat about finesse or drop, you know all the cards.

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7 also, but I know what is going to happen;)

 

When J does not drop, you will have cold sweats whether to finesse the heart at trick 10, or play for the drop. Discards may reveal something, but good opposition will not tell you anything.

But we are asked what contract we prefer, if we knew all cards. You don't have to sweat about finesse or drop, you know all the cards.

If we interpret the question this way, then I'd rather see all the cards before deciding.

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Even if I have to play it single dummy, I think it's a good enough grand slam to bid at IMPs. The two main chances are:

 

Jxx = 0.622 *3/7 = 0.267

Jx = 0.305 * 2/7 = 0.087

J singleton = 0.068 * 1/7 = 0.009

Subtotal = 0.363

 

Q onside = (1-0.363) / 2 = 0.318

 

So I've already got to 68%, without including either singleton Q offside or the showup squeeze when LHO has Jxxxx and xxx.

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Even if I have to play it single dummy, I think it's a good enough grand slam to bid at IMPs. The two main chances are:

 

Jxx = 0.622 *3/7 = 0.267

Jx = 0.305 * 2/7 = 0.087

J singleton = 0.068 * 1/7 = 0.009

Subtotal = 0.363

 

Q onside = (1-0.363) / 2 = 0.318

 

So I've already got to 68%, without including either singleton Q offside or the showup squeeze when LHO has Jxxxx and xxx.

I think the showup squeeze requires a star trek style device to beam you from dummy to your hand after running all the tricks.

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Even if I have to play it single dummy, I think it's a good enough grand slam to bid at IMPs.  The two main chances are:

 

Jxx = 0.622 *3/7 = 0.267

Jx = 0.305 * 2/7 = 0.087

J singleton = 0.068 * 1/7 = 0.009

Subtotal = 0.363

 

Q onside = (1-0.363) / 2 = 0.318

 

So I've already got to 68%, without including either singleton Q offside or the showup squeeze when LHO has Jxxxx and xxx.

You dont need all those calculations. Assuming they always bid 6nt at the other table, it's just good enough without the 10. Only Just.

 

Best Regards

 

Ole Berg

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Even if I have to play it single dummy, I think it's a good enough grand slam to bid at IMPs.  The two main chances are:

 

Jxx = 0.622 *3/7 = 0.267

Jx = 0.305 * 2/7 = 0.087

J singleton = 0.068 * 1/7 = 0.009

Subtotal = 0.363

 

Q onside = (1-0.363) / 2 = 0.318

 

So I've already got to 68%, without including either singleton Q offside or the showup squeeze when LHO has Jxxxx and xxx.

You dont need all those calculations. Assuming they always bid 6nt at the other table, it's just good enough without the 10. Only Just.

 

Best Regards

 

Ole Berg

I'm not sure I understand this. Without the 10, you will make 7NT when West holds Q, when East holds it singleton, and when East is void in hearts, all of which comes to about 57%.

 

That would not be good enough odds if there were only one other table (at IMPs - BAM is a different matter). Experience suggests that it is not good enough odds at matchpoints either, unless playing in a small field of uniformly high standard. One could imagine a number of pairs agreeing hearts at an early stage in the auction, finding out that Q is missing, and settling for a small slam in hearts. Without 10, I would be content with 6NT in most fields at matchpoints (the form of scoring specified in the original post).

 

Even with 10, I still consider that many pairs will find it difficult to bid to 7NT, and I would estimate that 6NT making seven would score pretty well.

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Why have cold sweats when the finesse is clearly percentage over the drop? You just finesse and pray :)

Is this really true? is it more likley then squeezing RHO? I know everyone is saying, yeah we make when queen is onside. But would you finesse at trick 11?

RHO can hold Qxx and J and is squeezed at trick 10, he has to come to doubleton heart.

 

I think you have to make some assumptions who has the last club (J), based on discards and table feel.

I agree its a pretty good 7, but trick 11,,,, grrr;)

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Opps

 

Edit

 

Transportation is a problem. Big. I would like to check if J is dropping. cash the ace of hearts, run my winners AND end up in south hand, and then decide finesse or squeeze but I can not do that. Maybe too keen on squeeze endings.:)

 

So you need to take finesse early, before cashing your dummy winners. You may go down 2, but hey, tomorrow is another day.

 

Disregard my previous posts.

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Even if I have to play it single dummy, I think it's a good enough grand slam to bid at IMPs.  The two main chances are:

 

Jxx = 0.622 *3/7 = 0.267

Jx = 0.305 * 2/7 = 0.087

J singleton = 0.068 * 1/7 = 0.009

Subtotal = 0.363

 

Q onside = (1-0.363) / 2 = 0.318

 

So I've already got to 68%, without including either singleton Q offside or the showup squeeze when LHO has Jxxxx and xxx.

You dont need all those calculations. Assuming they always bid 6nt at the other table, it's just good enough without the 10. Only Just.

 

Best Regards

 

Ole Berg

I'm not sure I understand this. Without the 10, you will make 7NT when West holds Q, when East holds it singleton, and when East is void in hearts, all of which comes to about 57%.

 

That would not be good enough odds if there were only one other table (at IMPs - BAM is a different matter). Experience suggests that it is not good enough odds at matchpoints either, unless playing in a small field of uniformly high standard. One could imagine a number of pairs agreeing hearts at an early stage in the auction, finding out that Q is missing, and settling for a small slam in hearts. Without 10, I would be content with 6NT in most fields at matchpoints (the form of scoring specified in the original post).

 

Even with 10, I still consider that many pairs will find it difficult to bid to 7NT, and I would estimate that 6NT making seven would score pretty well.

You're quite right, I miscalculated. I thuoght there were nine hearts in the combined hands. :P

 

Actually it only adds up to 55,6552%. Nowhere near the needed 58% (still assuming they always bid at least 6nt at the other table).

 

Can I have my 10 back, please?

 

Best Regards

 

Ole Berg

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