836K.C.asking Convention

[civill]

836/683KCasking without interference(836/683KC3/0/1/5)

Aces plus King of Trumps are key cards

[...4nt]

?

5C :0/3 key cards

5D :1/5

5H :2/4 with the trump queen

5S :2/4 without the trump queen

(836/683KC3015241240)

 

The first two responses may be reversed (playing 836/683KC5130).

5 NT does not necessarily ask for kings. The next 2 steps (other than trump suit) ask for kings or the queen.

That is:

I,over 5 C:

5 D/H asks for trump Q

5 H/S asks for kings

 

II,over 5 D:

5 H/S asks for trump Q

5 S/NT asks for kings

 

III,over 5 H if:

Clubs, Diamonds, or Hearts are trump:

5 S asks for kings

Spades are trump:

5 NT asks for kings

 

IV,over 5 S:

5 NT asks for kings

...

 

836/683KeyCard Kickback

Instead of bidding 4nt to request key cards (see 836/683KCasking for key card combinations), responder bids the

cheapest suit above the agreed suit. Thus,

4D is Kcasking for clubs

4H is Kcaking for diamonds

4S is Kcasking for hearts

4nt is Kcasking for spades.

 

Answer after interference

XOPY

X:Double;Redouble;

O:0 or odd;

P:pass;

Y:I/E-1 or even;

More combinations available but need written announcements between partnership in advance.

 

Original Webpage & more...

[Free]

What's the point in playing 1/5 when 5 never comes up? And what if you have ambiguity after 2 or 4 keycards (I know from experience with Turbo this can actually be a huge problem)? This sucks!

[civill]

While you bid the asking,you're impossible to known how many HCPs/KCs in the PD's hand;

But you could know whether the PD's stonger or weaker;

[civill]

It's seldom that 5-KC will come, but 5 might be change to 1 KC with 4 secondary KCs,such as trump Queen/suit Kings.

How about the modification?

[BillHiggin]

If you are worried about the 5 key card problem (the rest of us are not), then just think of the last two steps as 2/5 without Q and 2/5 with Q. Of course, it will always be 2 and never 5, but at least everything else is undamaged.

[Tomi2]

what aout this:

 

say 4NT is RKC for spades then:

 

1st step (5♣) = 2 Keycards or 0 Keycards w/o ♠Q or 4KC with ♠Q

next step then asks for ♠Q if you assume 2, else for kings

2nd step asks for kings if you assume 2KC in partners hand but dont need to know ♠Q

 

2nd step (5♦) = 1KC with ♠Q or 3w/o♠Q or 5 with ♠Q

next step asks for kings

 

3rd step (5♥) = 1KC w/o ♠Q or 3with ♠Q or 5 w/o ♠Q

nest step (5NT) asks for kings

 

4th step (5♠) = 0KC with♠Q or 4 w/o ♠Q

nest step (5NT) asks for kings

 

 

 

if you had a precise bidding before asking you will be able to read partners answer, else you count your own KCs like in normal 14-30 and try to figure it out, and if this doesnt help (then btw you wouldnt be able to reat answers like 1 or 4 as well) you have a 50% chance to have the ♠Q in your hand and will be surre what partner has.

 

So you will get Keycards AND ♠Q on a low level and can start to ask for kings maybe before 5 of your suit

 

of course you can (must) combine this sheme with kickback or something similar to avoid getting overboard

[civill]

Now,I could give you an all-in-1 resolution here:

 

***********************************************

II,8x6/68x KC asking wo/wt interference

 

strength(0/1/2/3) answer:

5♣ :<=strength key cards &, <=strength secondary KCs;

5♦ :<=strength KCs but, >strength secondary KCs;

5♥ :>strength KCs but, <=strength secondary KCs;

5♠ :>strength KCs &, >strength secondary KCs;

 

strongth define:

0:to weak responser;

1:to common;

2:to positive;

3:to strong;

 

U could call it as 8x6/68x KC2bid.

 

***********************************************

 

Else(further asking) maybe same as the top post;