gwnn Posted February 4, 2008 Report Share Posted February 4, 2008 Should pass be forcing by the pard of the 2NT opener? Is it a feasible treatment? et cetera? Quote Link to comment Share on other sites More sharing options...
Guest Jlall Posted February 4, 2008 Report Share Posted February 4, 2008 No Quote Link to comment Share on other sites More sharing options...
kfay Posted February 4, 2008 Report Share Posted February 4, 2008 What? Definitely not. Quote Link to comment Share on other sites More sharing options...
pclayton Posted February 4, 2008 Report Share Posted February 4, 2008 No. A better question does 2♣ - 2♦ - 2N create a force. Quote Link to comment Share on other sites More sharing options...
kfay Posted February 4, 2008 Report Share Posted February 4, 2008 No. A better question does 2♣ - 2♦ - 2N create a force. Better question: Who comes in after 2NT here that didn't come in after 2♣? :blink: But you're right it's probably a better question. Quote Link to comment Share on other sites More sharing options...
gwnn Posted February 4, 2008 Author Report Share Posted February 4, 2008 can somebody explain a little why it's such a bad idea that it doesn't even deserve being explained? Quote Link to comment Share on other sites More sharing options...
Guest Jlall Posted February 4, 2008 Report Share Posted February 4, 2008 can somebody explain a little why it's such a bad idea that it doesn't even deserve being explained? you could have 20 opp 0, the opps could be cold for game or slam with half the deck + distribution, the 2N opener is well defined so a forcing pass is not necessary, etc. Quote Link to comment Share on other sites More sharing options...
kfay Posted February 4, 2008 Report Share Posted February 4, 2008 I was playing in a sectional two weekends ago and opened 2NT, played there and went down 3 tricks since partner had a 0-count and I was constantly locked in hand. Nothing particularly bad about the opps' distribution, etc. Obviously that's a bit disappointing but the result was mirrored at the other table. I also wasn't shocked by anything that happened. If I'm forced by a 0-count pass by partner now I'm losing 2 IMPs on the hand at least, nevermind what happens at MPs. Quote Link to comment Share on other sites More sharing options...
gnasher Posted February 4, 2008 Report Share Posted February 4, 2008 can somebody explain a little why it's such a bad idea that it doesn't even deserve being explained? you could have 20 opp 0, the opps could be cold for game or slam with half the deck + distribution, the 2N opener is well defined so a forcing pass is not necessary, etc.That's the main disadvantage of a forcing pass. Before dismissing the idea, however, shouldn't one weigh this against the advantages? Personally, I don't think I have enough data to be able to judge - an overcall over a 2NT opening is hardly a common occurrence. Quote Link to comment Share on other sites More sharing options...
pclayton Posted February 4, 2008 Report Share Posted February 4, 2008 No. A better question does 2♣ - 2♦ - 2N create a force. Better question: Who comes in after 2NT here that didn't come in after 2♣? :blink: But you're right it's probably a better question. They don't have to come in later: 2♣ (2x) - pass (showing values) - (pass) - 2N - (3x) 2♣ (p) 2♦ (2x) 2N (3x) Quote Link to comment Share on other sites More sharing options...
Guest Jlall Posted February 4, 2008 Report Share Posted February 4, 2008 can somebody explain a little why it's such a bad idea that it doesn't even deserve being explained? you could have 20 opp 0, the opps could be cold for game or slam with half the deck + distribution, the 2N opener is well defined so a forcing pass is not necessary, etc.That's the main disadvantage of a forcing pass. Before dismissing the idea, however, shouldn't one weigh this against the advantages? Personally, I don't think I have enough data to be able to judge - an overcall over a 2NT opening is hardly a common occurrence. I think that this one is clearcut enough to just say "no," non pen X's and forcing bids work out fine. The advantages are small, are you going to use the X as penalty and a pass as like a takeout bid? Or are you going to use X as t/o without 4 of the other major and pass as t/o with 4 of the major? Or what? I just think this is obvious that pass should show a bad hand, I can't see it being playable that you're forced. Quote Link to comment Share on other sites More sharing options...
Guest Jlall Posted February 4, 2008 Report Share Posted February 4, 2008 No. A better question does 2♣ - 2♦ - 2N create a force. Better question: Who comes in after 2NT here that didn't come in after 2♣? :blink: But you're right it's probably a better question. They don't have to come in later: 2♣ (2x) - pass (showing values) - (pass) - 2N - (3x) This auction is obviously totally different since the pass showed values, thus you are in a force. 2♣ (p) 2♦ (2x) 2N (3x) This one is a good one. Quote Link to comment Share on other sites More sharing options...
Cascade Posted February 4, 2008 Report Share Posted February 4, 2008 We just play double for takeout. Too often you want to find your fit. Unless you are playing against lunatics who want to offer you free large penalties I think you will get more use out of a takeout double than a penalty double. Quote Link to comment Share on other sites More sharing options...
helene_t Posted February 4, 2008 Report Share Posted February 4, 2008 The question came up int the Ladderpuzzel (like MSC) of the Dutch BF magazine some years ago. The majority, but not all, of the experts voted for non-forcing. Quote Link to comment Share on other sites More sharing options...
pclayton Posted February 4, 2008 Report Share Posted February 4, 2008 2♣ (2x) - pass (showing values) - (pass) - 2N - (3x) This auction is obviously totally different since the pass showed values, thus you are in a force. Good point. Perhaps 2♣ (2x) dbl (bust) (p)2N - (3x) is a better example. Quote Link to comment Share on other sites More sharing options...
jtfanclub Posted February 4, 2008 Report Share Posted February 4, 2008 Too often you want to find your fit. Unless you are playing against lunatics who want to offer you free large penalties I think you will get more use out of a takeout double than a penalty double. If pass is forcing, then 2NT (3♦) X is takeout2NT (3♦) P P X is penalty oriented. I don't know that the idea is that weird. If opener is balanced, and responder can't double for takeout, most of the time they're not going to have much of a fit. So from that POV, sure, why not X? On the other hand, when you open 2NT and your partner has a balanced nothing, you're usually very happy when the opps interfere. It's a lot easier to take 5 tricks than 8, and you get a free entry into the nothing (since he's on opening lead). Why ruin it? My feeling is that in MPs you don't need to double because you're already getting a good board, and in IMPs the extra 50 or 100 isn't worth the ginormous swing when they do find some way to make it. But I don't think it's clear cut. Quote Link to comment Share on other sites More sharing options...
gnasher Posted February 4, 2008 Report Share Posted February 4, 2008 The advantages are small, are you going to use the X as penalty and a pass as like a takeout bid? Or are you going to use X as t/o without 4 of the other major and pass as t/o with 4 of the major? It's true that the advantages of such an approach would be limited. It might be better to use the pass artificially to make up for the space taken away by the overcall. For example 2NT (3D): pass = [Puppet] Stayman, double = transfer, 3H = transfer, etc2NT (3H): pass = 5+ spades, double = takeout, 3S = as without the overcall, etc2NT (3S): pass = 5+ hearts, double = takeout This has probably moved some way from what the original poster had in mind, though. Quote Link to comment Share on other sites More sharing options...
Cascade Posted February 4, 2008 Report Share Posted February 4, 2008 The advantages are small, are you going to use the X as penalty and a pass as like a takeout bid? Or are you going to use X as t/o without 4 of the other major and pass as t/o with 4 of the major? It's true that the advantages of such an approach would be limited. It might be better to use the pass artificially to make up for the space taken away by the overcall. For example 2NT (3D): pass = [Puppet] Stayman, double = transfer, 3H = transfer, etc2NT (3H): pass = 5+ spades, double = takeout, 3S = as without the overcall, etc2NT (3S): pass = 5+ hearts, double = takeout This has probably moved some way from what the original poster had in mind, though. I don't like methods that force you to get too high when you don't want to be. Over 15% of the time you will have 0-3 hcp opposite a limited 20-22 NT. I want to be able to stop out of game when I have these bad hands. This probably is even higher when the opponent has something that he wants to bid on. My simulation leapt to 40% when I gave one of the opponents 10+ hcp - yes I realize some and perhaps many overcalls after a 2NT opening might be on (much) less than 10 hcp. Quote Link to comment Share on other sites More sharing options...
awm Posted February 5, 2008 Report Share Posted February 5, 2008 It seems sort of strange to me that: 2NT-(bid)-Pass would be non-forcing whereas... (1NT)-X-(bid)-Pass is forcing. In the first case, opener has shown half the deck in his own hand. The opening side will virtually always have majority of the strength. Opponents probably have something for their bid (at least some shape) but in principle the opening side could still have the points for slam! In the second case, doubler has shown only something like 15-plus. Opener has shown something like 15-17 (assuming strong notrump). Neither side is all that likely to have the points even for game (much less slam), and either side could have the majority of the strength. Yet it seems like a lot of folks regard it as "obvious" that the first auction is NF and almost as "obvious" that the second auction is forcing? Seems weird to me. Anyways, I play all such auctions as NF under the reasoning that "there are no forcing auctions when someone on our side could still have a zero-count." However, use of such a rule puts me in a definite minority (there are many auctions such as the second one above, where one partner could easily have a zero-count and yet the majority plays forcing pass). Quote Link to comment Share on other sites More sharing options...
han Posted February 5, 2008 Report Share Posted February 5, 2008 Few play a double of a strong notrump as penalty and even those that do might not play the auction you refer to as forcing. Quote Link to comment Share on other sites More sharing options...
jdonn Posted February 5, 2008 Report Share Posted February 5, 2008 Adam I have never heard of 1NT X bid P as forcing. Certainly it can't be so common that it's some obvious assumption. I think the only place your agreement about forcing passes is way against mainstream thinking is after a 2♣ opening bid it's standard that all passes are forcing. Quote Link to comment Share on other sites More sharing options...
Cascade Posted February 5, 2008 Report Share Posted February 5, 2008 It seems sort of strange to me that: 2NT-(bid)-Pass would be non-forcing whereas... (1NT)-X-(bid)-Pass is forcing. In the first case, opener has shown half the deck in his own hand. The opening side will virtually always have majority of the strength. Opponents probably have something for their bid (at least some shape) but in principle the opening side could still have the points for slam! In the second case, doubler has shown only something like 15-plus. Opener has shown something like 15-17 (assuming strong notrump). Neither side is all that likely to have the points even for game (much less slam), and either side could have the majority of the strength. Yet it seems like a lot of folks regard it as "obvious" that the first auction is NF and almost as "obvious" that the second auction is forcing? Seems weird to me. Anyways, I play all such auctions as NF under the reasoning that "there are no forcing auctions when someone on our side could still have a zero-count." However, use of such a rule puts me in a definite minority (there are many auctions such as the second one above, where one partner could easily have a zero-count and yet the majority plays forcing pass). I am pretty much with you. I wouldn't play the (1NT) X (bid) Pass as forcing - as you say what do you do with a zero count. I have never understood these arguments. The only auctions when partner has a potential zero count that I would play as forcing are where opener has shown a game force. Quote Link to comment Share on other sites More sharing options...
barmar Posted February 5, 2008 Report Share Posted February 5, 2008 I've also never heard of (1NT) X (bid) Pass as forcing. But maybe the justification is that if responder had a decent hand he would presumably redouble, so (bid) tends to be weak, and that suggests that advancer should have something. Or maybe that overcaller shouldn't double 1NT if he's not willing to double a suit they run to or compete -- you generally shouldn't double a strong NT for penalties unless you have a source of tricks, not just a balanced 15 count. Since few experts play penalty doubles of strong NT these days, there's probably not too much concensus on this type of auction -- it just doesn't happen. Quote Link to comment Share on other sites More sharing options...
gnasher Posted February 5, 2008 Report Share Posted February 5, 2008 To play (1NT) X (bid) Pass as forcing is quite common in England, probably because a 12-14 notrump is so widespread. As usually played, advancer's pass promises values, and he bids immediately with a bad hand. The idea is to increase the chance of taking a penalty and improve the accuracy of any constructive bidding. Personally, I don't much like it, regardless of the notrump range. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.