Do you preempt?

[cnszsun]

Pass was indeed a good choice this time.

I bid 2♠ and got -1100.

[mike777]

Pass was indeed a good choice this time.

I bid 2♠ and got -1100.

Going for 1100 does seem a bit unlucky :)

 

But would expect a push as worse case :D

[jdonn]

But would expect a push as worse case :o

Not with someone who bid 1♠ at the other table.....

[lilboyman]

With my regular partners, we use the rule of 2/3/4. With only 5 winners 2 Spades would be the limit of this hand. Likewise, we would not open this 1 Spade because our discipline requires 2 defensive tricks to make an opening bid of 1 of a suit. The latter agreement keeps us out of 5 or 6 Spades when partner has 18 plus hand and to make intelligent decisions on competitive hands at the 5 level.

[mike777]

With my regular partners, we use the rule of 2/3/4.  With only 5 winners 2 Spades would be the limit of this hand.  Likewise, we would not open this 1 Spade because our discipline requires 2 defensive tricks to make an opening bid of 1 of a suit.  The latter agreement keeps us out of 5 or 6 Spades when partner has 18 plus hand and to make intelligent decisions on competitive hands at the 5 level.

I also use the rule of 2/3/4 but how are you counting 5 winners? In other words what method of counting winners do you use and why is that method better than the other ways?

 

I ask this since I would count this hand as 6 winners.....

 

1) We have 7 spades

2) I assume the remaining 6 spades are split evenly 2-2-2

3) therefore 6 winning spades.

[ArtK78]

If I were going to try to determine how many winners my hand would produce, I would assume that partner has a low singleton in my long suit, not that the suit is divided 2/2/2 around the table.

 

One should make conservative (but reasonable) assumptions in these situations.

[mike777]

If I were going to try to determine how many winners my hand would produce, I would assume that partner has a low singleton in my long suit, not that the suit is divided 2/2/2 around the table.

 

One should make conservative (but reasonable) assumptions in these situations.

That does not seem to be the method discussed in the Bridge Encyclopedia.

See pages 354 and 355.

 

"In Estimating the trick-taking strength of a hand, the holder assumes that his long suit will break evenly among the other three hands."

[han]

1) We have 7 spades

2) I assume the remaining 6 spades are split evenly 2-2-2

3) therefore 6 winning spades.

How often do you expect to make 6 spade tricks? Have you ever considered that question?

 

How many tricks should you expect to take from this suit on average? What if you assume that partner does not have spade honors that he would consider as increasing you trick taking potential?

[ArtK78]

If I were going to try to determine how many winners my hand would produce, I would assume that partner has a low singleton in my long suit, not that the suit is divided 2/2/2 around the table.

 

One should make conservative (but reasonable) assumptions in these situations.

That does not seem to be the method discussed in the Bridge Encyclopedia.

See pages 354 and 355.

 

"In Estimating the trick-taking strength of a hand, the holder assumes that his long suit will break evenly among the other three hands."

That is an optimistic assumption. It would make more sense if you held 6 or 8 cards in the suit, as then it is more reasonable to assume an even division of the cards in the suit around the table. A 3/2/2 division of the remaining 7 cards in a suit (or a 1/2/2 division of the remaining 5 cards in a suit) is far more likely than a 2/2/2 division of the 6 remaining cards in a suit.