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MP decision


Echognome

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[hv=d=e&v=n&n=s9843ht74dt42c753&w=sakt52hq52dj95c62&e=sqj6hj983dak87cq8&s=s7hak6dq63cakjt94]399|300|Scoring: MP

(1) - 2- (2) - P

(3) - Dbl - (P) - 4

(P) - P - (Dbl) - All Pass[/hv]

 

Yeah. I thought it fairly routine. I just got hosed when West found a (MP) double. They managed to misdefend and let me go one off, but -100 was not worth very many MPs. I can't really figure out why.

 

Of course, I also think it was pretty unlucky to catch partner with no values and no shape. The no values is not terribly surprising on the auction, but the no shape made it worse.

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Advancer's pass then 4 bid is aweful.

 

Either

a= raise to 3 and pass forevermore, or

b= pass, ...and pass overcaller's X if he makes one on the 2nd round.

 

vs this 3, EW should get 5 tricks: 2 's + 1 + 2 's

Yes, this is lucky. and Yes, on some days vs other 3's They will take 9 tricks.

 

But N has =no= ruffing potential and =no= values.

Stinky as it is, it's considerably easier to take 5 tricks rather than 10...

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Advancer's actions are completely normal.

He expects 3S to make, and is hoping for one off (or two off undoubled).

3S is making, so I don't know why -100 was so bad either.

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Advancer's pass then 4 bid is aweful.

 

Either

a= raise to 3 and pass forevermore, or

b= pass,  ...and pass overcaller's X if he makes one on the 2nd round.

 

vs this 3, EW should get 5 tricks:  2 's + 1 + 2 's

Yes, this is lucky.  and Yes, on some days vs other 3's They will take 9 tricks.

 

But N has =no= ruffing potential and =no= values.

Stinky as it is, it's considerably easier to take 5 tricks rather than 10...

Pass 3? Partner cannot beat this contract himself, -300 is better than -630

 

Before being resulting its ebtter to look closer because 3 makes against any defence

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The LOTT proved once more. North should assume a 1336 and do the math. 17 total tricks and 4 goes for 300 if 3 makes (both of which will be a bad at MP) while both contracts may be down one, or 3 goes for 300 if 4 makes. Pass, thus. It is more difficult at IMPs, not sure if I would have the guts to pass.

 

Edit: Oops, Frances is right, 3 makes. The LOTT disproved once more, that is.

Edited by helene_t
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The LOTT proved once more. North should assume a 1336 and do the math. 17 total tricks and 4 goes for 300 if 3 makes (both of which will be a bad at MP) while both contracts may be down one, or 3 goes for 300 if 4 makes. Pass, thus. It is more difficult at IMPs, not sure if I would have the guts to pass.

You forget 3 making overtrick when the field is at 4/5 :)

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Edit: Oops, Frances is right, 3 makes. The LOTT disproved once more, that is.

No, because 4C should have gone two off (I assume declarer made an unexpected diamond trick).

 

But playing matchpoints the LOTT isn't very helpful on this sort of hand:

- you can play for one off v. one off and pass (sweaty...)

- you can play for two off v. making and hope either they don't double, or they misdefend

 

perhaps a good idea to look at your opponents before deciding which is more likely!

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Okay 3 Spade makes this deal cause the Hearts are 3-3 and you cannot go wrong while playing the suits.

 

But is pass with the North hand really that bad?

If he expected a 1336 hand from pd, he will know that he will never ever produce a trick in 4 Club. He knows that they will fail to make this contract. Not just one down, but at least two.

So 4 Club is an always loosing option against all opps who will double them.

 

Pass can be a loosing option too, but with a little luck 3 Spade is down 1 at least.

(just change the Q and K of Diamonds and both contracs are one off...)

 

So I would go for a double against good opps with the north hand and write -670 in the scoresheet, good luck, this is just mps. Against bad opps, 4 Club is an alternative, they don´t double.

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Okay 3 Spade makes this deal cause the Hearts are 3-3 and you cannot go wrong while playing the suits.

 

But is pass with the North hand really that bad?

If he expected a 1336 hand from pd, he will know that he will never ever produce a trick in 4 Club. He knows that they will fail to make this contract. Not just one down, but at least two.

So 4 Club is an always loosing option against all opps who will double them.

 

Pass can be a loosing option too, but with a little luck 3 Spade is down 1 at least.

(just change the Q and K of Diamonds and both contracs are one off...)

 

So I would go for a double against good opps with the north hand and write -670 in the scoresheet, good luck, this is just mps. Against bad opps, 4 Club is an alternative, they don´t double.

The only reason opps must struggle a little to make 3 is the 2-2 break. If clubs were 3-1 the contract would alway be laydown, even if we make small changes (as switching Q/K).

 

Thus passing 3x has to be a losing decision. You'll still have a bad board if doubled, but it's not a certainty that opps will double you.

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I certainly agree with 2C. I think I would have passed 3S, partner is almost known to be broke on the auction.

Completely agree. Pard is busted. I'd say a 4=3=3=3 is a very likely shape. Do we really expect to buy this at 4 undoubled? Are we trying to salvage -100 in 4x'd against their 140? If so, MP is just too tough for me.

 

I love my hand too, but just because we have short spades doesn't give us the license to compete. We are totally outgunned here. Doubling gives them a fielder's choice between hitting 4 and bidding 4. I'll bet on many hands LHO would have a tough decision to bid on or pass, but we make his job easy this way.

 

Double will always result in declarer picking up pard's Qxx as well if they push to 4.

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Guest Jlall
You could easily be cold for 4H or 4C, you could go off 1 in 4C or 4H opposite nothing, or you could easily beat 3S X. I think it's criminal to let them play 3S. And believe it or not people don't always have 10 HCP to bid 2S here Oo.
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Advancer's pass then 4 bid is aweful.

 

Either

a= raise to 3 and pass forevermore, or

b= pass,  ...and pass overcaller's X if he makes one on the 2nd round.

 

vs this 3, EW should get 5 tricks:  2 's + 1 + 2 's

Yes, this is lucky.  and Yes, on some days vs other 3's They will take 9 tricks.

 

But N has =no= ruffing potential and =no= values.

Stinky as it is, it's considerably easier to take 5 tricks rather than 10...

Pass 3? Partner cannot beat this contract himself, -300 is better than -630

 

Before being resulting its better to look closer because 3 makes against any defence

It's not as simple as some seem to be claiming.

NS have the AK, the AK, and the Q is offside.

That's 5 tricks unless Opener can get 9 fast enough.

 

Opening from N is x. E must rise or NS can simply cash out for -1.

 

On T2, E can not play a or the 6 since that will cause -1.

Let's say E plays trump honor and does not overtake or play T (-1 if so).

 

T3, Declarer continues to draw trumps with the J

(Dummy still can not play 's or 6 w/o going -1)

S discards an encouraging

Again Declarer must follow small or it's -1.

 

T4. Now Declarer has to stop pulling trump or they go -1.

or are the only safe cards from E. Let's say a is played from Dummy.

S plays 2nd low as they ought.

Declarer must play Q from hand or 3 is -2.

 

etc. Yes, 3 makes DD. But the correct line is a tightrope that is relatively easy to fall off of.

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[hv=d=e&v=n&n=s9843ht74dt42c753&w=sakt52hq52dj95c62&e=sqj6hj983dak87cq8&s=s7hak6dq63cakjt94]399|300|Scoring: MP

(1) - 2- (2) - P

(3) - Dbl - (P) - 4

(P) - P - (Dbl) - All Pass[/hv]

 

The only reason opps must struggle a little to make 3♠ is the 2-2 ♣ break. If clubs were 3-1 the contract would alway be laydown, even if we make small changes (as switching ♦Q/K).

Maybe I have a blind spot, but if declarer has a 5341 hand and his pd 3343, they have more problems in making 3 Spade then now,or?

You start with two rounds of club, ruffed. Lets say he tried 2 rounds of trump and continues with?

I did not analyse in depth, but it is not too easy to handle this hand single dummy.

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[hv=d=e&v=n&s=s7hak6dq63cakjt94]133|100|Scoring: MP

(1) - 2 - (2) - P

(3) - ?[/hv]

 

Do you agree with 2?

 

What is your call now?

IMO...

[A] 2 = 10, X = 5

X = 10, P = 5, 3 N = 2, 4 = 1

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