I'm assuming that partner will bid like this EVERY time he has 54+ in the majors and less than 9. There are more unknown x's in spades, so there are more ways to construct a weak hand with 5(+)spades than 5(+)hearts.
It is very hard to come up with something completely new. Morath and Flodqvist came up with these responses to a strong club in 1971, but in their version 1D was 0-7 and 1H was unlimited.
Why? What if you play a strong pass with variable fert. V vs NV P 13+ 1C 0-7 any 1D 8-12 4+H 1H 8-12 4+S 1S 8-12 no M V vs V P 13+ 1C 8-12 4+H 1D 0-7 1H 8-12 4+S 1S 8-12 no M NV vs NV P 13+ 1C 8-12 4+H 1D 8-12 4+S 1H 0-7 1S 8-12 no M NV vs V P 13+ 1C 8-12 4+H 1D 8-12 4+S 1H 8-12 no M 1S 0-7 How many systems would that be? Where do you draw the line? The two system ban looks like a sloopy way of saying: You are not allowed to use different artificial meanings of the same opening bid.
Doesn't seem very useful to have the first step show zero honors OR three honors when scanning a doubleton. It might be that the first step, when scanning a doubleton, show zero or two honors (AK/AQ/KQ).
This is not fair, I am obv not Rodwell but I had no idea what the ruling for this kind of situation is, and from all my experiences with top pros very few know stuff like this. But I think it is fair to assume that Rodwell should know the correct ruling: http://www.acbl.org/about/lawsCommissionMembers.html
Suppose you have all two bids available as preempts, say in a strong club system with a very nebolous diamond. How would you use them? What if there was no NBO system restrictions?
1991 - Bermuda Bowl - Yokohama - Fallenius-Nilsland played something like: 1C 14+ 3+H or 17+ Bal or no 3+M 1D 14+ 3+S 1M 8-13 3+M 1N 14-16 2m 8-13 4+m 5+H or 4+om 5+S 2H/S/N 11-16 no 3+M I prefere to switch 1m: 1C 14+ 3+S or 17+ Bal or no 3+M 1D 14+ 3+H since Your are (a little) less vulnarable to preempts if the neboulus bid contains spades.