goobers

Well, you still got the 15th post (I was 14th). But you weren't the 15th poster.... Very tricksy!

I don't understand, 2D looks like an underbid, not an overbid. Or are we playing 2D as forcing here?

Because they all look high, his spade ace is probably not cashing anyway, and as long as partner pushes a 4th diamond back, you've already beaten the contract one trick

I guess he pitched the SA to encourage a 4th diamond. He's never getting his ace anyway.

Hopping the DK at trick 2, crossing, and leading a low club up?

I will cash the DA before leading a third heart.

...with the caveat that I thought about it for longer than I would have at the table. Also, these things tend to be easier when presented as a problem than when they come up in play. V Sigh, sadly true. I solved this problem, but I guarantee that I will not find this at the table. I guess it'll just take some more time before these things become second nature. (Will the opponents mind if I tank for 10 minutes at the table?)

Haven't read any of the replies because I don't wanna be influenced. Partner must have the DQ to beat this. In addition, we must cash our tricks IMMEDIATELY, or declarer will come home with his contract. Clubs and diamonds are obviously hopeless, and spades are obviously hopeless to us, but partner doesn't know it! Discard your SJ (or any spade, but why make life hard for partner?) We are playing partner for Kx or Jxx in hearts.

Hell, I would be glad I got another chance to get to 6S after my attempted signoff in 4.

Pitch your hearts.

The problem with these statements is that the envelopes in question contain a finite (and given amount of $5000 in the first envelope, call it Envelope A). All the other "probabilties" are meaningless. The only thing that matters in this problem is: Does Envelope B hold 1/2 as much as Envelope A or does it hold twice as much as Envelope A? B must equal either 1/2 A or 2A, and A is equal to $5000 in the problem as Justin has proposed it. So there is either $2500 or $10000 in envelope B, no other numbers matter. Person B is saying his Expected Value is greater if he switches envelopes. I happen to agree. His expected value is the sum total of what he receives by selecting B. (B = 1/2A) + (B = 2A) = (2B = 2 1/2) = (B = 1 1/4A) His expected value (on average) is 1 1/4 A. Lets say he does this 4 times, and meets the 50/50 odds. He draws 2500, 2500, 10000, 10000 = 25000/4 = 6250 which is greater than the 5000 he started with. If he does it 1000 times, 10000 times or a million times, his average expected value still works out to be 6250, which is greater than his current amount of $5000. QED. :D (Yes, I am sure there are flaws in my math arguments, but the logic is the same). There's something wrong with this. You say (B = 1/2A) + (B = 2A) but that isn't correct. Your value for A is inconsistent. It should either be 1/2A and A, or A and 2A, but not 1/2A and 2A. I think. This problem is giving me a headache.

If you want to pick up 4 tricks, you need to find doubleton K onside, but since we only want three... I guess we can start by cashing the CA. If the suit breaks 3-2, we always make 3 tricks no matter how we play it. If it breaks 4-1, then starting with the CA picks up the additional 4-1 break with the stiff K offside (where finessing a club honor would lose the suit). I don't see how you can pick up 3 tricks on any other 4-1 break, your spots just aren't good enough. So 68 + 28/5. Something like that?

Ok, LHO opens 1H Partner overcalls 1S 3'rd hand passes And you have Qx xxx Axxx KJxx Sadly you can not make a responsive x of partners bid. You also have a 10 count with a good fitting honor, but you lack a 5 card suit to bid and lack anything that resembles a stopper for NT. I think a 2S bid would be nearly unananimous in a bidding panel here (you have some extra values to make up for the lack of a 3rd trump). Backed into a corner here with no real reasonable alternatives; it's just that the impression I got was that some people were routinely raising with 2

I don't understand why people are raising with 2 card support

Lead the one that is your agreement, for me that is the 8, top of nothing. If I lead small here, partner will think I have 3 to an honor (or 4)

Well, I certainly failed to think fast, and I'm still thinking...

Okay so basically what happened was that my friend rebid 3N, which I thought was a bad idea basically because I understand that you're supposed to have a running suit for this bid, and that bad things are going to happen if they lead any major (hey, we've all responded with absolute garbage before...) I suggested 3C if he wanted to force, I thought 3D was a reasonable bid (being aware that I am an absolute absolute maximum), but I see now that a lot of people consider this hand good enough to force. Thanks all

x Ax KQJTxxx AKx You open 1D, partner of course responds 1S, your bid? To me, the options are 3D (preferred) or 3C, are there any other options? Is 3C even considered by people here?

I heard that pedophilia is a psychological complex that cannot be treated (barring something like chemical castration), but I am too lazy (don't care enough) to check if this is actually valid

In general, playing an unnecessarily high honor shows the honor(s) below it and denies the ones above it.

Basically 1♠ - 2x - 2y - 2♠ if it is available at that level, Helene said it all, I'm just condensing it.

Basically the difference between double and 1NT is whatever you agree it to be

2S really should promise 6, if you have a minimum with 5, then you've basically already bid your hand, partner is still there

2S can't be FSF, opener has already limited his hand, as I understand FSF auctions are initiated by responder Anyway, I guess 2S shows a spade stop with no interest in declaring NT

Damned x's. You're 4117