If 2♥ should cover the minimum opening bids with six hearts and some spade hands, I would prefer: 2♥ = either 10-14 with 6 hearts or a weak two-bid in spades 2♠ = 10-14 with 6 spades When responder has a fit for spades and a misfit for hearts, he would rather end into a 3-2 heart fit with less than half the deck. But I would still prefer 1♠ and probably 3♣ to be unbalanced, to have opposite a weak two-bid in spades responder be able to raise immediately to 3♠ or 4♠, and to have opposite a weak notrump with spades the undisclosed hand declare at spades. With hearts, I would suggest a kind of Kaplan Inversion/Granville: 1♥ = five or more hearts, 10-21, maybe 5332 if 11-13 (or a bad 14) ........1♠ = the equivalent of a one-notrump forcing answer, but may have four spades ................1N = clubs or diamonds ........................2♣ = to play in opener's minor ................................Pass = 11-15 with clubs ................................2♦ = 11-15 with diamonds ................................2♥ = 16+ with clubs ................................2♠ = 16+ with diamonds ........................2♦ = good preference to 2♥, 8+ ........................2♥ = bad preference, 4-7 ................2♣ = 4S ........................2♦ = 8+ ........................2♥ = bad preference, 4-7 ........................2♠ = bad preference, 4-7 ................2♦ = 5332, 11-13 ................................2♥ = to play ................................2♠ = 4=1=3=5 ................................3♣ = 6C ................2♥ = 6H, 10-14 (may have 4m) ........1N = five spades ................2♣ = 5H4C, but not 10-14 with 1=5=3=4, or 2=5=3=3, 11-13. Forcing ........................2♦ = relay ................................2♥ = 5H4C, either 2=5=2=4 or strong ................................2♠ = 2=5=3=3, 11-13 ................................3♣ = 5H5C, weak ................2♦ = 5H4D, or 10-14 with 1=5=3=4 (so that I end in a 3-3 minor fit with 5=1=3=4 opposite 1=5=3=4 rather than 5=1=4=3 opposite 2=5=3=3) ................2♥ = 6H, 10-14 (may have 4m) ................2♠ = minimum with 3S