Very easy in my system, where 1♣ = "nat. or bal.", incl. 4144, excl. 1444 ...1♦ = "4+ H" ......1♠ = "S" (incl. 4144) ...1♥ = "4+ S" 1♦ = "nat. unbal.", incl. 1444, excl. 4144 ...1♥ = "4+ S" ......1♠ = "H" (incl. 1444) ...1♠ = "4+ H", but also in (hypothetical) systems where 1♣ = "nat. or bal.", incl. 1444, excl. 4144 ...1♦ = "4+ S" ......1♠ = "H" (incl. 1444) ...1♥ = "4+ H" 1♦ = "nat. unbal.", incl. 4144, excl. 1444 ...1♥ = "4+ H" ......1♠ = "S" (incl. 4144) ...1♠ = "4+ S". I don't know how to solve the problem entirely if both 1444 and 4144 are in 1♦, as in Swedish/Polish Club, but I've seen some nice suggestions on this forum, such as straube's 3-suited 2♣ rebid over 1♦-1♠.