bgm

2nd deal should insert ♦8 ? It offers you a chance that E lead away from ♦9 while ♦J is off.

Require ♣A onside + catching 2Qs in 2 9-card fit. Stopping at game seems normal.

Using fixed-width/monospace font (like courier new) can help to have better alignment in table.

1. 2♠/2NT 的定義？ 2. 首攻後看見明手，6♥2♦，♣就是第9墩 3. 為甚麼偷得第9墩後還要貪心偷第10墩？

Moscito: [hv=d=e&v=0&b=14&a=1c(15+)p1d(FG)p1h(18+)p1s(m%201-suiter/2-suiter%20w/o%20%21s)p1n(%5BR%5D)p2c(%21c%201-suiter/%21c+%21h)p2d(%5BR%5D)p2h(%21c%201%20suiter)p2s(%5BR%5D)p3h(3316)p3s(QP%20ask)p4h(base+3%20%3D%209QP)p4s(DCB%20w/%20K%20parity)p4n(Even%20K)p5c(%5BR%5D)p6d(+6%3D2%21c%2C2%21h%2C1%21s%20Honors)p7nppp]133|100[/hv] At the stage of 9QP E knew that missing a Q as he got 8 QPs in ♠♥♣; Even K is as expected; and once confirm that W is not missing ♣Q can safely put down 7NT.

低花 Gazzilli 是其中一個可能: 1m - 1M 2om! = 17+ 強牌 (若 m = ♦ 也包含 ♦ + ♣的普通牌) .....2OM = 7/8+ 3M = 18-20 BAL with 4M 3OM/4om = SPL, with 5+m as good source of tricks 甚至可用 3NT 區分 5422 和 4432/4333

http://www.bridgebum.com/giorgio_belladonna.php 如果正確的話西家是 Eddie Kantar

坦白說，假如連這個人為叫品 2♦ 的第一層後續也沒有詳細約定，基本上都是在桌上瞎猜沒啥用 另外，逼局的牌有沒有考慮先叫♣表達 ♣ > ♠?

Looks like a trump control problem, supposing the black suits behave. Win ♦ A; concede a ♥; ruff ♦ return; ♣ A; concede a ♣; ruff ♦ return; concede a ♣. At this point both hand has 3 trumps, and 1 winning ♣. Either ruff ♦/♥ and can draw trump.

莊家第一墩跟出 ♥2，也讀不出首攻單張?!

Round 1 result, with 16-Board Continuous WBF VP 竞技桥牌 25 : 26 芳芳精确队 IMP Diff. = -1; VP 9.69 : 10.31 Seal Team 89 : 15 快乐桥牌岛 IMP Diff. = +74; VP 20.00 : 0.00 精细男队 51 : 31 扯淡群 IMP Diff. = +20; VP 15.00 : 5.00 精细女队 58 : 21 大汉二队 IMP Diff. = +37; VP 17.72 : 2.28 Sniper Team 18 : 35 大汉一队 IMP Diff. = -17; VP 5.61 : 14.39 Table by rank after round 1: Rank______VP_________Team 1_________20.00______Seal Team 2_________17.72______精细女队 3_________15.00______精细男队 4_________14.39______大汉一队 5_________10.31______芳芳精确队 6__________9.69______竞技桥牌 7__________5.61______Sniper Team 8__________5.00______扯淡群 9__________2.28______大汉二队 10_________0.00______快乐桥牌岛

Try with Moscito : 1♦...... 4+♥, 9-14 ...1♥... INV+ Relay 1♠...... 4+♠ ...1NT.. FG Relay 2♦...... 4-5♥, 4♠, 4-5♦, 0-1♣ ...2♥... Relay 2♠...... 4441 ...2NT.. Relay, QP ask 3NT..... Base = 6 ...4♣... Relay, DCB with King Parity 5♣...... Odd K, 1♦, 1/2 ♥, 1/2 ♠ Honors ...6♦... S/O, knowing 3 Ks w/o ♣A

這序列太遲表達♣單缺；運氣差的話♣跟♠對調5♥也不成

Moscito: [hv=d=n&v=0&b=1&a=p1cp1dp1hp2sp2np3cp3dp3hp3sp4dp7sppp]133|100[/hv] 1♣ = 15+ any 1♦ = FG 1♥ = 18+ any 2♠ = 5+♥,4♠ 2NT = Relay 3♣ = 0-1♦ 3♦ = Relay 3♥ = 4513 3♠ = QP ask 4♦ = 8QP 7♠ = S/O, partner must hold ♣AK♦A

在自然體系下這個序列空間緊張，很困難。 基本上整個牌型 1435 都想表達 (♠單(缺)，5+♣，3+♦支持，4♥不要示選錯誤)

西家鼓起勇氣在三階自願出套，北家加叫確認 ♥+♣ 雙套配合下加叫很基本吧

這是 BM2000 Level 5 A-16 的題目 題解裡也說明了當西家跟♦6 時上A不放小，以防西家單張♣及2/3張將牌 基本上題解的打法算是照顧了額外西家4張將牌的機會 (3343(最大機會), 蓋 ♦9 及持♣Q)； 當然清將前拔♥A也有微小♥8-0的風險，但肯定是化算的。

其實阻擊後都處理不了太多問題 1. ♠Qx ♥x ♦xxx ♣KQJxxxx 2. ♠xx ♥Ax ♦xx ♣QJTxxxx 3. ♠xx ♥Kx ♦xx ♣KQJTxxx

[hv=v=b&b=10&d=e&a=p1sp1np2cp2dp2hp2sp3cp3dp3np4cp4hp7nppp]400|300[/hv] 看到 Moscito 就試一試吧! 1♠ = 6+♦ or (54)+m's w/o 4M, 9-14 HCP 1NT = INV+ Relay 2♣ = (54)+m's w/o 4M 2♦ = FG Relay 2♥ = 5+♣, 4♦ 2♠ = Relay 3♣ = 2245 3♦ = QP ask 3NT = 8QP (base = 6; +3 = 8) 4♣ = DCB w/ K parity 4♥ = Even K, 0/3 ♣ Honors 7NT = S/O

Ignoring possible trump promotions When 3-2 break you are losing 2 ♠ tricks by playing ♠ KJT When 5-0 break or 4-1 break with AQ9x - x, you are losing 3 ♠ tricks to ♠ AQ9 When 4-1 break with singleton A: play small on first round with singleton Q: play K on first round with singleton 9: play K, J, or T on first round Therefore you should play K on first round.

這個雙明題很經典 首先第1墩要忍讓調整輸墩，但要規避西家於第2墩過早轉攻♥，明手必需放♠J，讓東家♠Q吃進。 視乎東家第2墩的回攻有不同的變化： 1. 回攻 ♥Q [hv=n=saj43hak4da92c876&e=sq765hqj9dqj876c2&s=s2ht87d543cakqjt9&b=1&d=n&a=1np5cppp&p=stsjsqs2hqh7h2hasas5d3s8s3s6cas9ckc3c6c2cqc4c7d6cjc5c8s7d4dkdad7s4dqctskc9h3h4&c=11]399|300[/hv] 東家第9墩解封♦Q，避免了紅花strip squeeze，卻引致一個有趣的 winkle 終局 2. 回攻 ♦6 [hv=n=saj43hak4da92c876&e=sq765hqj9dqj876c2&s=s2ht87d543cakqjt9&b=1&d=n&a=1np5cppp&p=stsjsqs2d6d3dkd2dtdad7d4c6c2cac3ckc4c7d8cqc5c8djcjh2d9s5h7h3hah9sas6h8s8s3s7cts9c9&c=11]399|300[/hv] 第3墩續攻♦，破壞了紅花單擠(威脅張♥10 ♦9)的聯通，卻引致雙擠 3. 回攻 ♠5 [hv=n=saj43hak4da92c876&e=sq765hqj9dqj876c2&s=s2ht87d543cakqjt9&b=1&d=n&a=1np5cppp&p=stsjsqs2s5d3s8s3dkdad6d4c6c2cac3ckc4c7d7cqc5c8dqcjh2s4s6ctskh4s7h7h3hah9sa&c=11]399|300[/hv] 第2墩再忍讓後(非必要)，第3墩轉攻♦破壞單擠後還有將吃擠牌 我猜其餘變化大多是紅花單擠的變形

4♥ by N/S 首攻♥，♥A定住(保留南家♥9)，提光6副旁門AK停在南家，最後交叉將吃黑花。 從叫牌的角度沒有多大意義，一切都要按概率辦事。

Perhaps a simple use of the frequency table is to compare Texas signoff at 4♥ and JTB signoff at 2♥, assume vulnerable. (No. of tricks: Total Points Difference, IMP Difference) 7-: -200, -5 8: -310, -7 9: -240, -6 10+: 450, +10 Then can calculate the expected IMP gain for 4♥ which is +5.322. I believe JTB with invitational raise will gain over direct 4♥, using the invitational rule you set. However due to the program limitation the result cannot be obtained here so let other helps to verify this.

Using Bridge Analyser Enter South's hand exactly as ♠T8 ♥K86543 ♦85 ♣KT8 North hand constrained as (4333), (4432) 5m(332) with 15-17 HCP East hand constrained as no 7 card suit, < 18 HCP Simulating 100000 deals for Q2. No. of deals satisfying 15 w/ 4♥: 7850 16-17 w/ 3+♥: 38895 So a total of 46745 out of 100000 deals, or around 46.745% Simulating 10000 deals for Q1 and Q3, running DD analysis calculate the number of tricks won when North declare a ♥ contract. Here is the frequency table (No. of tricks: Frequency) 5-: 0 6: 39 7: 330 8: 1639 9: 3830 10: 3358 11: 769 12: 32 13: 3 So a total of 4162 out of 10000 deals winning 10+ tricks in ♥, i.e. around 41.62% A total of 7992 out of 10000 deals winning 9+ tricks in ♥, i.e. around 79.92% in which 3830 deals winning exactly 9 tricks.

南家黑花持有經典的投入結構；實戰中能否及早讀出牌型很關鍵。