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cromar

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  1. I am a member of two rural clubs, each of which meets once per week during the winter months. In club A the championship is decided by taking the average of all percentage scores, provided a minimum number of attendances (usually 75% of total possible). In club B, the champions are those with the highest average of the best x scores, typically best 10 or best 12. As I see it, a drawback common to both methods is that no allowance is made for the strength of the opposition. For example, a pair beating 19 other pairs with a score of, say, 58% is rated inferior to a pair beating only 11 other pairs (on a bad weather night) with, say, 60%. Furthermore, the rationale behind method B leaves me baffled. I know of no other sport/pastime where one is permitted to disregard a poor score. This method can produce results like this: Pair A: 57, 58, 56, 52, 58, 57, 56, 52, 59, 57, 53, 49, 50, 52, 58. Overall average: 54.9%, Best 10: 56.9% Pair B: 60, 50, 59, 65, 41, 46, 56, 46, 59, 59, 43, 40, 60, 58, 57. Overall average: 53.3%, Best 10: 58.3% Is Pair A really inferior to Pair B? How is the championship decided in other clubs of this type? I would be grateful for members’ comments.
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